Calculate the percentage hydrolysis & the pH 0.02 M CH3COONH4. Kb(NH3) = 1.6 × 10^-5, Ka(CH3COOH) = 1.6 × 10^-5.
Calculate the percentage hydrolysis & the pH 0.02 M CH3COONH4. Kb(NH3) = 1.6 × 10^-5, Ka(CH3COOH) = 1.6 × 10^-5.
Calculate the percentage hydrolysis & the pH 0.02 M CH3COONH4. Kb(NH3) = 1.6 × 10^-5, Ka(CH3COOH) = 1.6 × 10^-5.
![pH of a solution of 0.1 M [CH3COONH4(aq)] is [given: Ka(CH3COOH) = Kb(NH4OH) = 1.8 x 10^-5)]](https://d10lpgp6xz60nq.cloudfront.net/web-thumb/644382825_web.png "pH of a solution of 0.1 M [CH3COONH4(aq)] is [given: Ka(CH3COOH) = Kb(NH4OH) = 1.8 x 10^-5)]")
pH of a solution of 0.1 M [CH3COONH4(aq)] is [given: Ka(CH3COOH) = Kb(NH4OH) = 1.8 x 10^-5)]
Calculate the percentage hydrolysis & the pH 0.02 M CH3COONH4. Kb(NH3) = 1.6 × 10^-5, Ka(CH3COOH) = 1.6 × 10^-5.
Identity correct statement (a)degree of hydrolysis decrease on doubling the concentration of aqueous solution of CH3COONH4 (b)for 1M CH3COOH pH=pKa/2 (c)salt hydrolysis depends on size of atom (d)all
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![Calculate the extent of hydrolysis and the pH of 0.02 M CH3COONH4. [ Kb (NH3) = 1.8 × 10^- 5,Ka (COOH) = 1.8 × 10^- 5 ]](https://d1hj4to4g9ba46.cloudfront.net/questions/1200266_999624_ans_e02120991ce8408c94c67fa9a8ab69a7.jpg "Calculate the extent of hydrolysis and the pH of 0.02 M CH3COONH4. [ Kb (NH3) = 1.8 × 10^- 5,Ka (COOH) = 1.8 × 10^- 5 ]")
Calculate the extent of hydrolysis and the pH of 0.02 M CH3COONH4. [ Kb (NH3) = 1.8 × 10^- 5,Ka (COOH) = 1.8 × 10^- 5 ]
Calculate the percentage hydrolysis & the pH 0.02 M CH3COONH4. Kb(NH3) = 1.6 × 10^-5, Ka(CH3COOH) = 1.6 × 10^-5.
110 Cap.11 Reazioni di idrolisi - Soluzioni saline ESEMPIO 1. Soluzione di acetato di sodio. Ac– + H2O ←→ AcH + OH–
![Welcome to Chem Zipper.com......: [3] CATIONIC AS WELL AS ANIONIC HYDROLYSIS:](https://2.bp.blogspot.com/-jLL0CmZPjjU/W9mhn_3BGMI/AAAAAAAArjY/mHuBJyZXhB4HTZAmUBpX0PcRh0pRt6aMQCLcBGAs/s1600/SH21.PNG "Welcome to Chem Zipper.com......: [3] CATIONIC AS WELL AS ANIONIC HYDROLYSIS:")
Welcome to Chem Zipper.com......: [3] CATIONIC AS WELL AS ANIONIC HYDROLYSIS:
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Calculate the percent hydrolysis of 0.02M of CH3COONH4 .Kb(NH3) = 1.6 × 10^-5 & Ka(CH3COOH) = 1.6 × 10^-5
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If pH of aqueous solution 10 at 25^oC then solution is:
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